vxx@lemmy.world to science@lemmy.worldEnglish · 2 days agoTomorrow The Earth Will Spin Faster Than Normal Making The Day 1.30 Milliseconds Shorterwww.iflscience.comexternal-linkmessage-square21fedilinkarrow-up1160arrow-down13
arrow-up1157arrow-down1external-linkTomorrow The Earth Will Spin Faster Than Normal Making The Day 1.30 Milliseconds Shorterwww.iflscience.comvxx@lemmy.world to science@lemmy.worldEnglish · 2 days agomessage-square21fedilink
minus-squarefloquant@lemmy.dbzer0.comlinkfedilinkEnglisharrow-up5·2 days agoI wonder if you could tell by measuring g today
minus-squarefloquant@lemmy.dbzer0.comlinkfedilinkEnglisharrow-up2·2 days agoI mean, I know you theoretically could, but would it be a “noticeable” difference? Like to the second or third decimal?
minus-squaresuicidaleggroll@lemmy.worldlinkfedilinkEnglisharrow-up8·edit-22 days agoIf my math is right…it will have an effect of approximately 0.0000000001 g Angular acceleration is r*w^2, so for a normal day that would be 6371000*(2*pi/86400)^2/g = 0.0034345580g On this accelerated day, it becomes 6371000*(2*pi/86399.9987)^2/g = 0.0034345581g That’s at the equator assuming a radius of 6371 km, which is a decent ballpark, the specific number won’t change the result much.
Are we going to fall off?
Not unless you’re at the front.
Phew
I wonder if you could tell by measuring g today
Yes. Yes, you could.
I mean, I know you theoretically could, but would it be a “noticeable” difference? Like to the second or third decimal?
If my math is right…it will have an effect of approximately 0.0000000001 g
Angular acceleration is r*w^2, so for a normal day that would be 6371000*(2*pi/86400)^2/g = 0.0034345580g
On this accelerated day, it becomes 6371000*(2*pi/86399.9987)^2/g = 0.0034345581g
That’s at the equator assuming a radius of 6371 km, which is a decent ballpark, the specific number won’t change the result much.